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Question: If ƒ is a continuous function such that \(\int_{0}^{x}{ƒ(t)}\)dt® as \|x\| ®, then for all k Ī R, ...

If ƒ is a continuous function such that 0xƒ(t)\int_{0}^{x}{ƒ(t)}dt® as |x| ®, then for all k Ī R, equation k2x2 + 0xƒ(t)\int_{0}^{x}{ƒ(t)}dt – a = 0 (a > 0) has–

A

All roots in (–, 0)

B

All roots in (0, )

C

Odd number of roots in (–, 0) and odd number of roots in (0, )

D

None of these

Answer

Odd number of roots in (–, 0) and odd number of roots in (0, )

Explanation

Solution

Let g(x) = k2x2 +0xf(t)dta\int_{0}^{x}{f(t)dt - a} … (1)

Since, a > 0 and 0xf(t)dt\int_{0}^{x}{f(t)dt \rightarrow \infty} as x ® ±  (given)

Ž g(0) = 0 + 00f(t)dta\int_{0}^{0}{f(t)dt - a}= –a < 0

and g() =  +  – a =  > 0

also, g(–) =  +  – a =  > 0

Ž g(x) is continuous in (–, )

Hence, g(x) = 0 has odd number of roots in (–, 0) and odd number of roots in (0, )