Question
Mathematics Question on integral
if a∫bxn+(16−x)nxndx=6, then
A
a=4,b=12,n∈R
B
a=2,b=14,n∈R
C
a=−4,b=20,n∈R
D
a=2,b=8,n∈R
Answer
a=2,b=14,n∈R
Explanation
Solution
a∫bxn+(16−x)nxndx=6....(i) Let a+b=16, then by property a∫b(16−x)n+xn(16−x)ndx=6....(ii) Adding(i) and (ii), we get a∫b1⋅dx=12 ⇒b−a=12 Solving a+b=16 and b−a=12, we get a=2,b=14 and n∈R