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Question

Question: If \(\int _ { - a } ^ { a } \sqrt { \frac { a - x } { a + x } } d x = k \pi\) then \(k =\)...

If aaaxa+xdx=kπ\int _ { - a } ^ { a } \sqrt { \frac { a - x } { a + x } } d x = k \pi then k=k =

A

a- a

B

2a- 2 a

C

2a2 a

D

aa

Answer

aa

Explanation

Solution

Since aaaxa+xdx=aπ\int _ { - a } ^ { a } \sqrt { \frac { a - x } { a + x } } d x = a \pi

So comparing it with the given value, we get k=ak = a