Question

If in Young's double slit experiment distance between two slits is twice the wavelength of light used. If distance between slits and screen is D then distance of first maxima from central maxima is –

• A.
• B. $\frac{D}{2}$
• C. $\frac{D}{\sqrt{3}}$
• D. $\sqrt{3}D$

Answer 1

Answer: (C)

$\frac{D}{\sqrt{3}}$

Answer 2

Dx = d sin q = 2l sin q = l[for I^st max.]

\ sin q = $\frac{1}{2}$

\ q = 30⁰

Now tan 30⁰ = $\frac{y}{D}$ ̃ y = $\frac{D}{\sqrt{3}}$