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Question: If in the reaction \(2NH_{3}\) is that part of \(N_{2}\) which dissociates, then the number of moles...

If in the reaction 2NH32NH_{3} is that part of N2N_{2} which dissociates, then the number of moles at equilibrium will be.

A

3

B

1

C

NH3NH_{3}

D

N2N_{2}

Answer

N2N_{2}

Explanation

Solution

PCl5(g)PCl_{5}(g) ⇌ 2.4×10−32.4 \times 10^{- 3}

total mole at equilibrium −2.4×10−34.2×102- 2.4 \times 10^{- 3}4.2 \times 10^{2}