Question

If in the case of a radio-isotope, the value of half-life(T1/2) and decay constant(λ) are identical in magnitude, then their value should be

• A. $\frac{0.693}{2}$
• B. (0.693)1/2
• C. (0.693)2
• D. 0.693

Answer 1

Answer: (B)

(0.693)1/2

Answer 2

The correct answer is option (B): (0.693)1/2

We know,

$t_\frac{1}{2}=\frac{0.693}{k\,or\,\lambda}$ i.e. $0.693=\lambda^2\Rightarrow\lambda=(0.693)^\frac{1}{2}$