Question

If in a nuclear fusion reaction, mass defect is $0.3\%$ then energy released in fusion of 1 kg mass

• A. $27 \times 10^{10}J$
• B. $27 \times 10^{11}J$
• C. $27 \times 10^{12}J$
• D. $27 \times 10^{13}J$

Answer 1

Answer: (D)

$27 \times 10^{13}J$

Answer 2

: Here,

$\Delta m = 0.3\% of1kg = \frac{0.3}{100}kg = 3 \times 10^{- 3}kg$

$\therefore E = (\Delta m)c^{2} = 3 \times 10^{- 3} \times (3 \times 10^{8})^{2} = 27 \times 10^{13}J$