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Question: If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is....

If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is.

A

1.25×1071.25 \times 10^{7}

B

2.25×1072.25 \times 10^{7}

C

3.25×1073.25 \times 10^{7}

D

0.25×1070.25 \times 10^{7}

Answer

1.25×1071.25 \times 10^{7}

Explanation

Solution

E=Δmc2=0.5×10−3×(3×108)2=4.5×1013jE = \Delta mc^{2} = 0.5 \times 10^{- 3} \times (3 \times 10^{8})^{2} = 4.5 \times 10^{13}j

⇒E=4.5×10133.6×106=1.25×107kWH.\Rightarrow E = \frac{4.5 \times 10^{13}}{3.6 \times 10^{6}} = 1.25 \times 10^{7}kWH.