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Question

Physics Question on Nuclear physics

If in a nuclear fission, piece of uranium of mass 5.0g5.0\, g is lost, the energy obtained in kWhkWh is

A

1.25×1071.25 \times 10^7

B

2.25×1072.25 \times 10^7

C

3.25×1073.25 \times 10^7

D

0.25×1070.25 \times 10^7

Answer

1.25×1071.25 \times 10^7

Explanation

Solution

As we know, energy E=Δmc2E = \Delta mc^2
=0.5×103×(3×108)2=0.5 \times10^{-3} \times\left( 3 \times10^{8}\right)^{2}
=4.5×1013= 4.5 \times10^{13}
E=4.5×10133.6×106E = \frac{4.5 \times10^{13}}{3.6 \times10^{6}}
=1.25×107kWh= 1.25 \times10^{7} kWh