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Question: If in a DABC, a<sup>2</sup> cos<sup>2</sup> A = b<sup>2</sup> + c<sup>2</sup>, then –...

If in a DABC, a2 cos2 A = b2 + c2, then –

A

A <π4\frac { \pi } { 4 }

B

π4\frac { \pi } { 4 }< A <π2\frac { \pi } { 2 }

C

A >π2\frac { \pi } { 2 }

D

A = π2\frac { \pi } { 2 }

Answer

A >π2\frac { \pi } { 2 }

Explanation

Solution

cos A = =

= π2\frac { \pi } { 2 }.