Question

If in a coded language, MASTER is written as 79 7 115 121 31 109 then LAUGH will be written as
(Note: - Do NOT include any spaces in your answer)

Answer 1

Let's find out how "MASTER" is written as "79 7 115 121 31 109" and decode the logic behind it to apply the same to "LAUGH".
Understanding the Pattern:
By comparing the positions of the letters in "MASTER" with their corresponding encoded values:
1. M (13th letter) → 79
2. A (1st letter) → 7
3. S (19th letter) → 115
4. T (20th letter)→ 121
5. E (5th letter) → 31
6. R (18th letter)→ 109
It appears there is a transformation involved. Let's break it down:
- M (13) -> 79
- A (1) -> 7
- S (19) -> 115
- T (20) -> 121
- E (5) -> 31
- R (18) -> 109
Pattern Identification:
1. M (13) -> 79
- This might be encoded as $13 \times 6 + 1$
2. A (1) -> 7
- This might be encoded as $1 \times 6 + 1$
3. S (19) -> 115
- This might be encoded as $19 \times 6 + 1$
4. T (20) -> 121
- This might be encoded as $20 \times 6 + 1$
5. E (5) -> 31
- This might be encoded as $5 \times 6 + 1$
6. R (18) -> 109
- This might be encoded as $18 \times 6 + 1$
This doesn't work consistently. Instead, let's consider an alternative pattern:
By using the formula $(Position \times 6) + 1$:
1. M (13) -> $(13 \times 6) + 1 = 79$
2. A (1) -> $(1 \times 6) + 1 = 7$
3. S (19) -> $(19 \times 6) + 1 = 115$
4. T (20) -> $(20 \times 6) + 1 = 121$
5. E (5) -> $(5 \times 6) + 1 = 31$
6. R (18) -> $(18 \times 6) + 1 = 109$
Now, let's apply this formula to "LAUGH":
1. L (12th letter) -> $(12 \times 6) + 1 = 73$
2. A (1st letter) -> $(1 \times 6) + 1 = 7$
3. U (21st letter) -> $(21 \times 6) + 1 = 127$
4. G (7th letter) -> $(7 \times 6) + 1 = 43$
5. H (8th letter) -> $(8 \times 6) + 1 = 49$
Thus, "LAUGH" would be written as73 7 127 43 49.