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Question: If \({Im}\left( \frac{z_{1}}{z_{2}} \right) = 0\) then the value of \({Re}(z_{1}z_{2}) = 0\) is....

If Im(z1z2)=0{Im}\left( \frac{z_{1}}{z_{2}} \right) = 0 then the value of Re(z1z2)=0{Re}(z_{1}z_{2}) = 0 is.

A

Im(z1z2)=0{Im}(z_{1}z_{2}) = 0

B

z1z_{1}

C

z2z_{2}

D

arg(z1/z2)=0,arg(z_{1}/z_{2}) = 0,

Answer

z2z_{2}

Explanation

Solution

2xy=242xy = 24=−21+3i×1−3i1−3i\frac { - 2 } { 1 + \sqrt { 3 } i } \times \frac { 1 - \sqrt { 3 } i } { 1 - \sqrt { 3 } i } x+iy=±(a+bi)\sqrt{x + iy} = \pm (a + bi)

x+iy=a2−b2+2iabx=a2−b2,x + iy = a^{2} - b^{2} + 2iabx = a^{2} - b^{2},.