Question
Question: If \(\frac { 1 } { 1 ^ { 2 } } + \frac { 1 } { 2 ^ { 2 } } + \frac { 1 } { 3 ^ { 2 } }\)+ …….to ¥ = ...
If 121+221+321+ …….to ¥ = 6π2 then
121+321+521 + ………to ¥ equals to :
A
p2/12
B
p2/8
C
p2/18
D
None
Answer
p2/8
Explanation
Solution
S1 =121+221+321+ …….to ¥ = 6π2 ….(1)
̃ S2 = 221+421+621 + ….. to ¥
=
̃ S2 = 41⋅6π2 …….(2)
hence 121+321+521 + ……to ¥ = S1 – S2
= 6π2−24π2=243π2=8π2