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Question

Question: If \(g ^ { 2 } + f ^ { 2 } = c\), then the equation\(x ^ { 2 } + y ^ { 2 } + 2 g x + 2 f y + c = 0\)...

If g2+f2=cg ^ { 2 } + f ^ { 2 } = c, then the equationx2+y2+2gx+2fy+c=0x ^ { 2 } + y ^ { 2 } + 2 g x + 2 f y + c = 0will represent.

A

A circle of radius g

B

A circle of radius f

C

A circle of diameterc\sqrt { c }

D

A circle of radius 0

Answer

A circle of radius 0

Explanation

Solution

Radius of given circle =g2+f2c= \sqrt { g ^ { 2 } + f ^ { 2 } - c }

g2+f2=cg ^ { 2 } + f ^ { 2 } = c (given) , \therefore Radius = 0.