Question

If I(x) = \int e^{sin^2x}$$(cos \;x \;sin \;2x - sin \;x)dx and I (0) = 1, then $I(π/3)$ is equal to

• A. $-e^{\frac{3}{4}}$
• B. $e^{\frac{3}{4}}$
• C. $-\frac{1}{2}e^{\frac{3}{4}}$
• D. $\frac{1}{2}e^{\frac{3}{4}}$

Answer 1

Answer: (D)

$\frac{1}{2}e^{\frac{3}{4}}$

Answer 2

The Correct Option is (D): $\frac{1}{2}e^{\frac{3}{4}}$