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Question

Mathematics Question on Integration by Parts

If I =sec4xcosec2xdx \int sec ^4x \, cosec ^2x \,dx =K tan ^3x +L tan x+M cot x + const, then

A

K=13K= \frac {1}{3}L = 1,M = 2

B

K=13K= \frac {1}{3}L = 2,M = -1

C

K = - 1, L = 0, M = 1

D

none of these

Answer

K=13K= \frac {1}{3}L = 2,M = -1

Explanation

Solution

Answer (b) K=13K= \frac {1}{3}L = 2,M = -1