Question
Mathematics Question on Integrals of Some Particular Functions
If I1=0∫3πf(cos2x)dx and I2=0∫πf(cos2x)dx, then
A
I1=I2
B
3I1=I2
C
I1=3I2
D
I1=5I2
Answer
I1=3I2
Explanation
Solution
I1=30∫πf(cos2x)dx=3I2
[∵ period is π]
If I1=0∫3πf(cos2x)dx and I2=0∫πf(cos2x)dx, then
I1=I2
3I1=I2
I1=3I2
I1=5I2
I1=3I2
I1=30∫πf(cos2x)dx=3I2
[∵ period is π]