Question
Question: If \[{I_1} = \int\limits_0^1 {{2^{{x^2}}}dx} ,{I_2} = \int\limits_0^1 {{2^{{x^3}}}dx} ,{I_3} = \int\...
If I1=0∫12x2dx,I2=0∫12x3dx,I3=1∫22x2dx and I4=1∫22x3dx then
(A) I3>I4
(B) I3=I4
(C) I1>I2
Solution
Firstly, we will check that for the integrals I1 and I2, which function gives larger value in the interval [0,1]. Then we will check the same for the integrals I3 and I4. And on comparing, we will get the result.
Complete step by step solution:
First, we will take the interval I1 and I2 because they have the same interval 0 to 1.
Square of any value from the interval 0 to 1 is greater than the cube of that value.
⇒x2>x3 in the interval [0,1].
Also, we can see that
i.e. ∫x2>∫x3 in the interval [0,1].
We can also see that
⇒2x2>2x3 in the interval [0,1].
Therefore, the value of 0∫12x2dx is greater than the value of 0∫12x3dx.
⇒0∫12x2dx>0∫12x3dx
Hence, I1>I2.
Now, we can see that the cube of any value in the interval [1,2] is greater than the square of that value.
The value of x3 in the interval [1,2] is larger than the value of x2.
Hence, x3>x2 in the interval [1,2].
The integration of x3 is greater than the integration of x2 in the interval [1,2].
Hence,
⇒∫x3>∫x2 in the interval [1,2].
Therefore, the value of 1∫22x3dx is greater than the value of 1∫22x2dx.
⇒1∫22x3dx>1∫22x2dx
Hence, I4>I3.
Therefore I3=I4
**Hence option (C) is correct
i.e. I1>I2 **
Note:
The given integrals are definite integrals. Definite integrals are the integrals whose limits are given. The definite integrals are mainly used to calculate the area of the region.