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Question: If half life of radium is 77 days. Its decay constant in day will be....

If half life of radium is 77 days. Its decay constant in day will be.

A

3×10−133 \times 10^{- 13}/day

B

9×10−39 \times 10^{- 3}/day

C

1×10−31 \times 10^{- 3}/day

D

6×10−36 \times 10^{- 3}/day

Answer

9×10−39 \times 10^{- 3}/day

Explanation

Solution

λ=0.693T1/2=0.69377=9×10−3/day\lambda = \frac{0.693}{T_{1/2}} = \frac{0.693}{77} = 9 \times 10^{- 3}/day.