Question

If half cell reaction $A + e^- \rightarrow A^-$ has a large negative reduction potential, it follows that

• A. A is readily reduced
• B. A is readily oxidized
• C. $A ^-$ is readily reduced
• D. $A^-$ is readily oxidized

Answer 1

Answer: (D)

$A^-$ is readily oxidized

Answer 2

Gain of electrons is reduction and A has a large negative reduction potential. This means the reduction potential of A is very smaller. A is difficult to reduce to $A^-$. Therefore, $A^-$ is easy to oxidise to A.