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Question: If h is planck’s constant, the momentum of a photon of wavelength 0.01Åis :...

If h is planck’s constant, the momentum of a photon of wavelength 0.01Åis :

A

102h10^{- 2}h

B

)hh

C

)102h10^{2}h

D

)1012h10^{12}h

Answer

)1012h10^{12}h

Explanation

Solution

: Momentum of photon , p=Ec=hυcp = \frac{Ec}{} = \frac{h\upsilon}{c}

Where E is the energy of a photon and c is the velocity of light

p=hccλ=hλ=h0.01×1010=1012h[υ=cλ]\therefore p = \frac{hc}{c\lambda} = \frac{h}{\lambda} = \frac{h}{0.01 \times 10^{- 10}} = 10^{12}h\left\lbrack \because\upsilon = \frac{c}{\lambda} \right\rbrack