Question

If $g:R \rightarrow R,$ , ∀ n ≥ 1 then $g(x) = x^{2}(gof)(x)$ is equal to

• A. 3
• B. 3/2
• C. ¾
• D. 3/8

Answer 1

Answer: (D)

3/8

Answer 2

= 2(3ⁿ – 1)

⇒ t₁ + t₂ + …..+ t_n = 2(3ⁿ – 1)

We can do t_n = S_n – S_n–1

⇒ t_n = 2(3ⁿ –1) – 2(3^n–1 – 1)

= 2[3ⁿ – 3^n–1] = 4.3^n–1 Now,

=$\frac { 1 } { 4 }$. =$\frac { 1 } { 4 }$. $\frac { 1 } { \left( 1 - \frac { 1 } { 3 } \right) }$ =$\frac { 3 } { 8 }$