Question

If galvanometer has 500 W resistance and R = 5000 W, then what should be the resistance connected to galvanometer in parallel to it so that its deflection reduces to half –

• A. 544 W
• B. 500 W
• C. 455W
• D. None

Answer 1

Answer: (C)

455W

Answer 2

G = $\frac{RS}{R - S}$ \

500 = $\frac{5000S}{5000 - S}$

\ S = 455 W