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Question

Mathematics Question on Sequence and series

If g1,g2g_1, g_2 are two geometric means and a1a_1 is the arithmetic mean between two positive numbers, then the value of g12g2+g22g1\frac{g_{1}^{2}}{g_{2}} + \frac{g_{2}^{2}}{g_{1}} is

A

2a1 2a_1

B

a1a_1

C

a12\frac{a_{1}}{2}

D

3a13a_1

Answer

2a1 2a_1

Explanation

Solution

Let a,g1,g2,ba, g_{1}, g_{2}, b are in G.PG. P. g12=ag2 \therefore g_{1}^{2} = ag_{2} g12g2=a...(i) \Rightarrow \frac{g_{1}^{2}}{g_{2}} = a \quad ...\left(i\right) Also, g22=bg1 g_{2}^{2} = bg_{1} g22g1=b...(ii) \Rightarrow \frac{g_{2}^{2}}{g_{1}} = b \quad...\left(ii\right) Adding (i)\left(i\right) and (ii)\left(ii\right), we get g12g2+g22g1=a+b\frac{g_{1}^{2}}{g_{2} }+\frac{g_{2}^{2}}{g_{1}} = a+b =2a1= 2a_{1} [ a,a1,b\because a, a_{1}, b are in A.PA.P.]