Question: If $f(x) = y.$ and g(x) = $\frac{1}{3}(x + 4)$ then $\frac{1}{3}(x - 4)$ is...

Question

If $f(x) = y.$ and g(x)

= $\frac{1}{3}(x + 4)$ then $\frac{1}{3}(x - 4)$ is

Answer 1

Solution

= $\left\{ \begin{array} { c c } \sin ^ { 2 } x + 1 & n \neq n \pi , n = 0 , \pm 1 , \ldots \ldots \ldots \ldots \ldots \ldots \ldots . . . . . . . . . . . . \\ 5 & \text { other wise } \end{array} \right.$

thus

Question: If \(f(x) = y.\) and g(x) = \(\frac{1}{3}(x + 4)\) then \(\frac{1}{3}(x - 4)\) is...

Solution