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Question: If f(x) = x<sup>3</sup> + bx<sup>2</sup> + cx + d, 0 \< b<sup>2</sup>\< c, then f(x) is –...

If f(x) = x3 + bx2 + cx + d, 0 < b2< c, then f(x) is –

A

Strictly increasing

B

Locally maximum

C

Locally minimum

D

Bounded

Answer

Strictly increasing

Explanation

Solution

f ¢(x) = 3x2 + 2 bx + c

By B2 – 4ac = 4b2 – 12 c

= 4 (b2 – 3c) < 0 as b2 < c

a > 0, D < 0

̃ f ¢(x) > 0  ∀ x.

̃ x is strictly increasing.