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Question

Question: If f(x) = \|x\| + \|x – 1\|, g(x) = e<sup>x</sup> + e<sup>–x</sup> then f(x) ÷ g(x) is –...

If f(x) = |x| + |x – 1|, g(x) = ex + e–x then f(x) ÷ g(x) is –

A

Continuous every where

B

Continuous at x = 0 only

C

Discontinuous at x = 1

D

None of these

Answer

Continuous every where

Explanation

Solution

So f(x) ÷ g(x) ← c