Question
Question: If f(x) = \|x\| + \|x – 1\|, g(x) = e<sup>x</sup> + e<sup>–x</sup> then f(x) ÷ g(x) is –...
If f(x) = |x| + |x – 1|, g(x) = ex + e–x then f(x) ÷ g(x) is –
A
Continuous every where
B
Continuous at x = 0 only
C
Discontinuous at x = 1
D
None of these
Answer
Continuous every where
Explanation
Solution

So f(x) ÷ g(x) ← c