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Question: If f(x) = tan<sup>–1</sup>(g(x)) {where g(x) is monotonically increasing for 0 \< x \<p/2} then f(x)...

If f(x) = tan–1(g(x)) {where g(x) is monotonically increasing for 0 < x <p/2} then f(x) is-

A

Increasing in (0, p/2)

B

Decreasing in (0, p/2)

C

Increasing in (0, p/4)

D

Decreasing in (p/4, p/2)

Answer

Increasing in (0, p/2)

Explanation

Solution

f ¢(x) = g(x)1+(g(x))2\frac{g'(x)}{1 + (g(x))^{2}}> 0 " x Î (0, p/2)

{Q g¢(x) > 0 as g(x) is monotonically increasing}