Question
Question: If f(x) = tan<sup>–1</sup>(g(x)) {where g(x) is monotonically increasing for 0 \< x \<p/2} then f(x)...
If f(x) = tan–1(g(x)) {where g(x) is monotonically increasing for 0 < x <p/2} then f(x) is-
A
Increasing in (0, p/2)
B
Decreasing in (0, p/2)
C
Increasing in (0, p/4)
D
Decreasing in (p/4, p/2)
Answer
Increasing in (0, p/2)
Explanation
Solution
f ¢(x) = 1+(g(x))2g′(x)> 0 " x Î (0, p/2)
{Q g¢(x) > 0 as g(x) is monotonically increasing}