Question

If f(x) = $\sqrt{2}$Where [.] is G.I.F. then –

• A. f(x) is differentiable at x = 0
• B. f(x) is differentiable at x = 2
• C. f(x) is continuous but not differentiable at x=0
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

continuity f(2⁺) = 2 + 2 sin (0) = 2

f(2^–) = 3 + 2 sin (0) = 3 discontinuous at x = 2

at x = 0 f(0⁺) = 2 (0) – 0– 0 × sin (0[0]) = 0

f(0^–) = 2(0) – (–1) + 0 × sin(0–(–1))

discontinuous at x = 0