Question

If f(x) = $\left( \frac{x^{a}}{x^{b}} \right)^{a + b}$. $\left( \frac{x^{b}}{x^{c}} \right)^{b + c}$.$\left( \frac{x^{c}}{x^{a}} \right)^{c + a}$, then f´(x) is equal to

• A. 1
• B. 0
• C. x^a+b+c
• D. None of these

Answer 1

Answer: (B)

0

Answer 2

**Sol. **f(x) – $(x)^{a^{2} - b^{2}}$× $(x)^{b^{2} - c^{2}}$× $(x)^{c^{2} - a^{2}}$

f(x) = $(x)^{a^{2} - b^{2} + b^{2} - c^{2} + c^{2} - a^{2}}$= (x)⁰ = 1

f´(x) = 0