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Question: If \(f(x) = \left| \begin{matrix} 1 & x & (x + 1) \\ 2x & x(x - 1) & (x + 1)x \\ 3x(x - 1) & x(x - 1...

If f(x)=1x(x+1)2xx(x1)(x+1)x3x(x1)x(x1)(x2)(x+1)x(x1)f(x) = \left| \begin{matrix} 1 & x & (x + 1) \\ 2x & x(x - 1) & (x + 1)x \\ 3x(x - 1) & x(x - 1)(x - 2) & (x + 1)x(x - 1) \end{matrix} \right|, then

f(100)f(100) is equal to

A

0

B

1

C

100

D

–100

Answer

0

Explanation

Solution

1 & x & (x + 1) \\ 2x & x(x - 1) & (x + 1)x \\ 3x(x - 1) & x(x - 1)(x - 2) & (x + 1)x(x - 1) \end{matrix} \right|$$ Applying $C_{3} \rightarrow C_{3} - C_{2}$, we get $f(x) = \left| \begin{matrix} 1 & x & 1 \\ 2x & x(x - 1) & 2x \\ 3x(x - 1) & x(x - 1)(x - 2) & 3x(x - 1) \end{matrix} \right| = 0$. Hence $$f(100) = 0$$