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Question: If f(x) = \(g(x) = 1 + \sqrt{x}\) Then \(f(g(x)) = 3 + 2\sqrt{x} + x,\)...

If f(x) = g(x)=1+xg(x) = 1 + \sqrt{x}

Then f(g(x))=3+2x+x,f(g(x)) = 3 + 2\sqrt{x} + x,

A

Is equal to 1

B

Is equal to – 1

C

Is equal to 0

D

Does not exist.

Answer

Is equal to 0

Explanation

Solution

f(0 + h) = lim⁡h→0\lim _ { h \rightarrow 0 } h sin = 0 sin ∞ = 0

f(0 – h) = lim⁡h→0\lim _ { h \rightarrow 0 } – h sin = 0 sin (–∞) = 0