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Question: If f(x) = \(\frac{x}{1 + \tan x}\); x Î (0, p/2) then the function contains –...

If f(x) = x1+tanx\frac{x}{1 + \tan x}; x Î (0, p/2) then the function contains –

A

A point of maxima

B

A point of minima

C

Neither maximum nor minimum

D

) None of these

Answer

A point of maxima

Explanation

Solution

As the derivative dydx\frac{dy}{dx} =cos2xx2cos2x(1+xtanx)2\frac{\cos^{2}x - x^{2}}{\cos^{2}x(1 + x\tan x)^{2}}changes its sign form + ve to –ve point of maximum.