Question

If frequency of electromagnetic wave is 60 MHz and it travels in air along z direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave (in m) is :

• A. 2.5
• B. 10
• C. 5
• D. 2

Answer 1

Answer: (C)

5

Answer 2

Given: - Frequency of the electromagnetic wave: $f = 60 \, \text{MHz} = 60 \times 10^6 \, \text{Hz}$ - Speed of light in air: $c = 3 \times 10^8 \, \text{m/s}$

Step 1: Calculating the Wavelength

The wavelength $\lambda$ of an electromagnetic wave is given by the formula:

$\lambda = \frac{c}{f}$

Substituting the given values:

$\lambda = \frac{3 \times 10^8 \, \text{m/s}}{60 \times 10^6 \, \text{Hz}}$

Simplifying:

$\lambda = \frac{3 \times 10^8}{60 \times 10^6} \, \text{m}$ $\lambda = \frac{3}{60} \times 10^2 \, \text{m}$ $\lambda = 5 \, \text{m}$

Conclusion:

The wavelength of the electromagnetic wave is $5 \, \text{m}$.