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Question: If $\frac{p}{q}=\frac{19}{5}+\frac{2}{7}-2.4+(\frac{4.8}{2.4})^2$, where p/q is a simplest form, the...

If pq=195+272.4+(4.82.4)2\frac{p}{q}=\frac{19}{5}+\frac{2}{7}-2.4+(\frac{4.8}{2.4})^2, where p/q is a simplest form, then find the sum of the digits of q.

Answer

8

Explanation

Solution

The problem requires us to simplify a given expression to find a fraction pq\frac{p}{q} in its simplest form and then calculate the sum of the digits of the denominator qq.

The given expression is: pq=195+272.4+(4.82.4)2\frac{p}{q} = \frac{19}{5} + \frac{2}{7} - 2.4 + \left(\frac{4.8}{2.4}\right)^2

Step 1: Convert decimal numbers to fractions. We convert the decimal numbers into their fractional forms: 2.4=2410=1252.4 = \frac{24}{10} = \frac{12}{5} 4.8=4810=2454.8 = \frac{48}{10} = \frac{24}{5}

Step 2: Simplify the term involving the square. The term (4.82.4)2\left(\frac{4.8}{2.4}\right)^2 can be simplified as follows: (4.82.4)2=(24/512/5)2\left(\frac{4.8}{2.4}\right)^2 = \left(\frac{24/5}{12/5}\right)^2 The division of fractions simplifies to: (2412)2=(2)2=4\left(\frac{24}{12}\right)^2 = (2)^2 = 4

Step 3: Substitute the simplified terms back into the equation. Now, substitute the fractional forms and the simplified square term back into the original equation: pq=195+27125+4\frac{p}{q} = \frac{19}{5} + \frac{2}{7} - \frac{12}{5} + 4

Step 4: Combine like terms. We can group the fractions with the same denominator: pq=(195125)+27+4\frac{p}{q} = \left(\frac{19}{5} - \frac{12}{5}\right) + \frac{2}{7} + 4 pq=19125+27+4\frac{p}{q} = \frac{19 - 12}{5} + \frac{2}{7} + 4 pq=75+27+4\frac{p}{q} = \frac{7}{5} + \frac{2}{7} + 4

Step 5: Find a common denominator and add the fractions. To add these rational numbers, we find the least common multiple (LCM) of the denominators 5, 7, and 1 (for the integer 4). The LCM of 5 and 7 is 5×7=355 \times 7 = 35. Convert each term to an equivalent fraction with the denominator 35: 75=7×75×7=4935\frac{7}{5} = \frac{7 \times 7}{5 \times 7} = \frac{49}{35} 27=2×57×5=1035\frac{2}{7} = \frac{2 \times 5}{7 \times 5} = \frac{10}{35} 4=41=4×351×35=140354 = \frac{4}{1} = \frac{4 \times 35}{1 \times 35} = \frac{140}{35} Now, add these fractions: pq=4935+1035+14035\frac{p}{q} = \frac{49}{35} + \frac{10}{35} + \frac{140}{35} pq=49+10+14035\frac{p}{q} = \frac{49 + 10 + 140}{35} pq=59+14035\frac{p}{q} = \frac{59 + 140}{35} pq=19935\frac{p}{q} = \frac{199}{35}

Step 6: Verify if the fraction is in simplest form. The fraction obtained is 19935\frac{199}{35}. For this to be in simplest form, the greatest common divisor (GCD) of the numerator (199) and the denominator (35) must be 1. The prime factorization of the denominator is 35=5×735 = 5 \times 7. We check if the numerator, 199, is divisible by 5 or 7:

  • 199 is not divisible by 5 because its last digit is not 0 or 5.
  • For divisibility by 7: 199÷7=28199 \div 7 = 28 with a remainder of 33 (199=7×28+3199 = 7 \times 28 + 3). So, 199 is not divisible by 7. Since 199 is not divisible by any prime factor of 35, the fraction 19935\frac{199}{35} is indeed in its simplest form.

Step 7: Identify q and calculate the sum of its digits. From the simplest form pq=19935\frac{p}{q} = \frac{199}{35}, we have p=199p = 199 and q=35q = 35. The digits of qq are 3 and 5. The sum of the digits of qq is 3+5=83 + 5 = 8.