Question
Question: If \(\frac{\alpha}{2}\)then amp\(\alpha\)– amp\(\frac{1 + \sqrt{3}i}{\sqrt{3} + 1}\)...
If 2αthen ampα– amp3+11+3i
A
0
B
3π
C
−3π
D
6π
Answer
−3π
Explanation
Solution
amp(z) z2=π+[ar⥂g6mu(zˉ)]
If 2αthen ampα– amp3+11+3i
0
3π
−3π
6π
−3π
amp(z) z2=π+[ar⥂g6mu(zˉ)]