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Question: If \(\frac{3x + 4}{(x + 1)^{2}(x - 1)} = \frac{A}{(x - 1)} + \frac{B}{(x + 1)} + \frac{C}{(x + 1)^{2...

If 3x+4(x+1)2(x−1)=A(x−1)+B(x+1)+C(x+1)2\frac{3x + 4}{(x + 1)^{2}(x - 1)} = \frac{A}{(x - 1)} + \frac{B}{(x + 1)} + \frac{C}{(x + 1)^{2}}, then A=A =

A

−12\frac{- 1}{2}

B

154\frac{15}{4}

C

74\frac{7}{4}

D

−14\frac{- 1}{4}

Answer

74\frac{7}{4}