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Question: If \(\frac{1}{ab'}\) + \(\frac{1}{ba'}\)= 0, then lines \(\frac{x}{a}\)+ \(\frac{y}{b}\)= 1 and \(\f...

If 1ab′\frac{1}{ab'} + 1ba′\frac{1}{ba'}= 0, then lines xa\frac{x}{a}+ yb\frac{y}{b}= 1 and xb′\frac{x}{b'}+ya′\frac{y}{a'}= 1 are

A

Parallel

B

Inclined at 600 to each other

C

Perpendicular to each other

D

Inclined at 300 to each other

Answer

Perpendicular to each other

Explanation

Solution

Q a1a2 + b1b2 = 1ab′\frac{1}{ab'} + 1a′b\frac{1}{a'b}= 0

Therefore, the lines are perpendicular.