Question

If $\frac{10}{13} + \frac{24}{13}i$ and $\frac{10}{13} - \frac{24}{13}i$then $a + ib > c + id$ equals.

• A. $b = 0,c = 0$
• B. $b = 0,d = 0$
• C. $a = 0,c = 0$
• D. $a = 0,d = 0$

Answer 1

Answer: (C)

$a = 0,c = 0$

Answer 2

$\frac { z _ { 1 } } { z _ { 2 } } = \frac { 4 + 5 i } { - 3 + 2 i } \times \frac { - 3 - 2 i } { - 3 - 2 i }$ $z_{1} = a + ib = c - id = {\bar{z}}_{2}$

=$(\because a = c$