Question

If $(\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})$, Find the value of x and y.

Answer 1

It is given that $(\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})$.

Since the ordered pairs are equal, the corresponding elements will also be equal.

$(\frac {x}{3}+1, \frac {y-2}{3}) = (\frac {5}{3}, \frac {1}{3})$

Therefore,

$\frac {x}{3}+1=\frac {5}{3}$

⇒ $\frac{x}{3} = \frac{5}{3} -1,\frac{y-2}{3} = \frac{1}{3}$

⇒$\frac{x}{3} = \frac{2}{3}, y = \frac{1}{3}+\frac{2}{3}$

⇒ x=2, y=1