Question
Question: If \(\frac { 3 + 5 + 7 + \ldots \ldots . + \mathrm { n } \text { terms } } { 5 + 8 + 11 + \ldots \l...
If 5+8+11+……+10 terms 3+5+7+…….+n terms = 7 then value of n is –
A
35
B
36
C
37
D
40
Answer
35
Explanation
Solution
210(10+9×3)2n(6+(n−1)2) = 7 ̃ = 7
̃ 5(37)n(n+2) = 7 ̃ n = 35