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Question

Mathematics Question on Sequence and series

If 1(1+d)(1+2d)+1(1+2d)(1+3d)+...+1(1+9d)(1+10d)=1,\frac{1}{(1+d)(1+2d)}+\frac{1}{(1+2d)(1+3d)}+...+\frac{1}{(1+9d)(1+10d)}=1, then the value of 50d is____. (d > 0)

A

50

B

60

C

25

D

30

Answer

25

Explanation

Solution

The Correct answer is option is (C) : 25