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Question

Physics Question on work, energy and power

If force F=5i^+3j^+4k^\vec{ F }= 5 \hat{ i }+3 \hat{ j }+4 \hat{ k } makes a displacement of s=6i^5k^\vec{ s }=6 \hat{ i }-5 \hat{ k }, work done by the force is :

A

10 unit

B

1225122\sqrt{5} unit

C

51225\sqrt{122} unit

D

20 unit

Answer

10 unit

Explanation

Solution

Work done =Fs=\vec{ F } \cdot \vec{ s } =(5i^+3j^+4k^)(6i^5k^)=(5 \hat{ i }+3 \hat{ j }+4 \hat{ k }) \cdot(6 \hat{ i }-5 \hat{ k }) =(5i^+3j^+4k^)(6i^+0j^5k^)=(5 \hat{ i }+3 \hat{ j }+4 \hat{ k }) \cdot(6 \hat{ i }+0 \hat{ j }-5 \hat{ k }) =(30+020)=10=(30+0-20)=10 unit