Question
Physics Question on work, energy and power
If force F=5i^+3j^+4k^ makes a displacement of s=6i^−5k^, work done by the force is :
A
10 unit
B
1225 unit
C
5122 unit
D
20 unit
Answer
10 unit
Explanation
Solution
Work done =F⋅s =(5i^+3j^+4k^)⋅(6i^−5k^) =(5i^+3j^+4k^)⋅(6i^+0j^−5k^) =(30+0−20)=10 unit