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Question

Physics Question on Motion in a plane

If force F=3i^+4j^2k^\vec F=3\hat i+4\hat j−2\hat k acts on a particle having position vector 2i^+j^+2k^2\hat i+\hat j+2\hat k then, the torque about the origin will be

A

3i^+4j^2k^3\hat i+4\hat j−2\hat k

B

10i^+10j^+5k^-10\hat i+10\hat j+5\hat k

C

10i^+5j^10k^10\hat i+5\hat j-10\hat k

D

10i^+j^5k^10\hat i+\hat j-5\hat k

Answer

10i^+10j^+5k^-10\hat i+10\hat j+5\hat k

Explanation

Solution

r=r×F\vec r = \vec r \times \vec F
= (2i^+j^+2k^2\hat i+\hat j+2\hat k) x (3i^+4j^2k^3\hat i+4\hat j−2\hat k)
= 10i^+10j^+5k^-10\hat i+10\hat j+5\hat k

So, the correct option is (B).