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Question: If for a thermocouple \(T_{n}\) is the neutral temperature, \(T_{c}\) is the temperature of the cold...

If for a thermocouple TnT_{n} is the neutral temperature, TcT_{c} is the temperature of the cold junction and TiT_{i} is the temperature of inversion, then

A

Ti=2TnTcT_{i} = 2T_{n} - T_{c}

B

Tn=Ti2TcT_{n} = T_{i} - 2T_{c}

C

Ti=TnTcT_{i} = T_{n} - T_{c}

D

None of these

Answer

Ti=2TnTcT_{i} = 2T_{n} - T_{c}

Explanation

Solution

Tn=Ti+TC2T _ { n } = \frac { T _ { i } + T _ { C } } { 2 } \Rightarrow Ti=2TnTCT_{i} = 2T_{n} - T_{C}