Question

If for a particle executing SHM, the equation of SHM is given as y= a cos $\omega$t Then which of the following graph represents the variation in its potential energy?

• A. II, IV
• B. I, III
• C. III, IV
• D. I, II

Answer 1

Answer: (B)

I, III

Answer 2

The potentiaI energy is maximum at extreme positions (where y = $\pm$ a) and zero at mean position. So, graph I is correct. Also, from $\, \, \, y=acos \omega t$ $\, \, \, \, \, \, \, \, \, \, \, \, y=\pm a \, at \, times \, t=0$ Hence, I graph III is also correct.