Question

If for 2A2B(g) $\rightleftharpoons$ 2A2(g) + B2(g), Kp = TOTAL PRESSURE (at equilibrium) and starting the dissociation from 4 mol of A2B then :

• A. Degree of dissociation of A2B will be (2/3).
• B. Total no. of moles at equilibrium will be (14/3).
• C. At equilibrium the no. of moles of A2B are not equal to the no. of moles of B2
• D. At equilibrium the no. of moles of A2B are equal to the no. of moles of A2

Answer 1

Answer: (A)

Degree of dissociation of A2B will be (2/3).

Answer 2

2A2B(g) $\rightleftharpoons$ 2A2(g) + B2(g) KP = P

$2 \alpha$

$\Rightarrow \quad 2 \alpha ^ { 3 } = ( 1 - \alpha ) ^ { 2 } ( 4 + 2 \alpha )$ $2 \alpha ^ { 3 } = \left( 1 + \alpha ^ { 2 } - 2 \alpha \right) ( 4 + 2 \alpha )$