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Question: If foci of hyperbola lie on y = x and one of asymptote is y = 2x, then equation of hyperbola, given...

If foci of hyperbola lie on y = x and one of asymptote is

y = 2x, then equation of hyperbola, given that it passes through (3, 4) is-

A

x2 – y252\frac{5}{2}xy + 5 = 0

B

2x2 – 2y2 + 5xy + 5 = 0

C

2x2 + 2y2 + 52\frac{5}{2}xy + 5 = 0

D

None of these

Answer

None of these

Explanation

Solution

Major axis of hyperbola bisects asymptote

\ equation of other asymptote is y = x2\frac{x}{2}

equation of hyperbola is (y –2x) (x –2y) + k = 0

put (3, 4)