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Question: If flowers are cut and dipped in dilute NaCl solution then A. Transpiration is low B. Endo-osmos...

If flowers are cut and dipped in dilute NaCl solution then
A. Transpiration is low
B. Endo-osmosis occurs
C. No bacterial growth takes place
D. Absorption of solute inside flower cell takes place

Explanation

Solution

Endosmosis is the development of the water inside the cells when the cell is put in a hypotonic arrangement.

Complete answer:
Osmosis is a process in which the solvent molecules move from a low concentration to a higher concentration through a semipermeable membrane. If a cell is put in a solution, it can be differentiated based on its concentration level relative to the cell. Hypotonic solutions will have low concentration than the subject cell, hypertonic solution will have higher concentration than the subject cell, and isotonic solution will have same concentration as of the subject cell.

At the point when a plant is developing in the soil, the roots ingest supplements and water by methods for a cycle called osmosis. Osmosis includes the movement of particles dependent on the weight of the different conditions. Particles will in general move from high strain to low weight situations. At the point when you include salt, this draws the liquid out of the plant cells. This helps bring down the weight inside the stem and empowers osmosis. It's much similar to the manner in which we feel parched in the wake of eating something salty.

So, the correct answer is option B.

Note: Summarizing it up, Reason behind this conclusion is that a dilute NaCl solution will behave as a hypotonic solution which will cause the water to flow from the lower concentration (solution) to higher concentration (flower cells). This will cause the flower to swell up due to the process of endosmosis.