Question
Question: If \(f(x) = \sin \left[ {{\pi ^2}} \right]x + \cos \left[ { - {\pi ^2}} \right]x\) then \(f'(x)\) is...
If f(x)=sin[π2]x+cos[−π2]x then f′(x) is , here [π2] and [−π2] greatest integer function not greater than its value
Choose the correct option.
A. sin9x+cos9x
B. 9cos9x−10sin10x
C. 0
D. −1
Solution
For solving this particular question which involves greatest integer function. We must know that for [x], the value of the greatest integer function is given by the larger value of the integer whose value is less than or equal to x.
Complete step by step solution:
It is given that f(x)=sin[π2]x+cos[−π2]x , where [π2] and [−π2] greatest integer function not greater than its value.
Let us take given equation,
f(x)=sin[π2]x+cos[−π2]x
As we know, the value of π is 3.14 .
Therefore , the value of π2 is 9.86 .
Therefore, we get ,
⇒[π2]=9 and [−π2]=−10
As we know [ ] denotes the greatest integer function not greater than its value.
Now, put this result in the given equation,
⇒f(x)=sin9x+cos(−10)x
We know that cos(−x)=cosx . therefore,
=sin9x+cos10x
Now differentiate the above equation with respect to x.
⇒f′(x)=9cos9x−10sin10x
Hence , we get the required result .
Therefore, we can say that option (B) is correct .
Note:
The other name for greatest integer function is floor function , the name floor is given because the graph we obtain from the greatest integer function looks like a step.
Greatest integer function is represented by using a square bracket that is [ ] .
For [x] , the value of the greatest integer function is given by the larger value of the integer whose value is less than or equal to x .
Differentiation of sinx is cosx and cosx is minus sinx.
Differentiation of sinax is acosx and cosax is minus asinx.
Greatest integer function will always give an integer value.